Question

A xenon compound 'A' upon partial hydrolysis gives XeO₂F₂. The number of lone pair of electrons present in compound A is _________. (Round off to the Nearest Integer)

Hint:

All fluorides of Xenon ($XeF_2, XeF_4, XeF_6$) undergo hydrolysis; $XeF_6$ is the only one that can undergo partial hydrolysis.

Answer 1

Correct Answer: 1

Step 1: Partial hydrolysis sequence: $XeF_6 \xrightarrow{H_2O} XeOF_4 \xrightarrow{H_2O} XeO_2F_2$. Thus, $A$ is $XeF_6$.
Step 2: In $XeF_6$, Xe has 8 valence $e^-$. 6 are used for bonds with F.
Step 3: Lone pair $= (8 - 6)/2 = 1$.