Given: Original weft yarn: 24 tex, pick density = 25/cm New weft yarn: 6 tex (same packing density)
Key Concepts: Yarn diameter ($d$) $\propto \sqrt{{tex}}$ To maintain fabric cover: $\frac{d}{{spacing}}$ must stay constant Spacing ($s$) = $\frac{1}{{pick density}}$
Step 1: Find Yarn Diameter Ratio \[ \frac{d_2}{d_1} = \sqrt{\frac{6}{24}} = \sqrt{\frac{1}{4}} = \frac{1}{2} \] New yarn is half the diameter of original.
Step 2: Maintain Fabric Cover \[ \frac{d_1}{s_1} = \frac{d_2}{s_2} \implies d_1 P_1 = d_2 P_2 \] \[ P_2 = P_1 \times \frac{d_1}{d_2} = 25 \times 2 = 50 \] Final Answer: \[ \boxed{50} \]
Based only on the conversation below, identify the logically correct inference:
“Even if I had known that you were in the hospital, I would not have gone there to see you”, Ramya told Josephine.
The paper as shown in the figure is folded to make a cube where each square corresponds to a particular face of the cube. Which one of the following options correctly represents the cube? Note: The figures shown are representative.
