Question:

A vertical double-acting steam engine develops 75 kW at 250 r.p.m. The maximum fluctuation of energy is 30 percent of the work done per stroke. The maximum and minimum speeds are not to vary more than 1 percent on either side of the mean speed. What is the approximate mass of the flywheel required? If the radius of gyration is 0.6 m.

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For flywheel design, use the relationship between energy fluctuation and the moment of inertia to determine the required mass.
Updated On: Sep 17, 2025
  • 347 kg
  • 447 kg
  • 547 kg
  • 647 kg
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The Correct Option is B

Solution and Explanation

Step 1: Apply the formula for the mass of the flywheel.
The mass of the flywheel is related to the fluctuation of energy and the moment of inertia. Using the energy fluctuation formula, we calculate the required mass. Step 2: Use given values.
Given that the power developed by the engine is 75 kW and the radius of gyration is 0.6 m, we can calculate the mass required for the flywheel using the standard equation for energy fluctuation. Final Answer: \[ \boxed{447 \, \text{kg}} \]
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