Step 1: Define the unit direction vector.
Since \( \mathbf{a} \) makes equal angles with the coordinate axes, let the direction cosines be \( l, m, n \).
For a vector making equal angles with all three axes:
\[
l = m = n.
\]
Since the sum of the squares of the direction cosines is always 1, we write:
\[
l^2 + m^2 + n^2 = 1.
\]
Substituting \( l = m = n \):
\[
3l^2 = 1.
\]
\[
l^2 = \frac{1}{3}, \quad l = \frac{1}{\sqrt{3}}.
\]
Thus, the direction cosines are:
\[
\left(\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}\right).
\]
Step 2: Find the components of \( \mathbf{a} \).
The vector \( \mathbf{a} \) is given by:
\[
\mathbf{a} = |\mathbf{a}| \times (\text{direction cosines}).
\]
Given that \( |\mathbf{a}| = 5\sqrt{3} \), we compute:
\[
\mathbf{a} = 5\sqrt{3} \left( \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}} \right).
\]
\[
\mathbf{a} = (5,5,5).
\]
Final Answer:
\[
\mathbf{a} = 5\hat{i} + 5\hat{j} + 5\hat{k}.
\]