Step 1: Understanding the VNTR genotypes.
The number of genotypes in a population depends on the number of alleles at the locus and how these alleles can combine. For a locus with 15 alleles, the genotypes can be formed by any combination of two alleles (one from each parent), including the possibility of having the same allele from both parents (homozygous) or different alleles (heterozygous).
Step 2: Calculating the number of genotypes.
For a locus with \( N \) alleles, the number of genotypes possible is given by the formula:
\[
\text{Number of genotypes} = \frac{N(N + 1)}{2}.
\]
This formula counts both the homozygous genotypes (where both alleles are the same) and the heterozygous genotypes (where alleles are different).
For \( N = 15 \) alleles:
\[
\text{Number of genotypes} = \frac{15(15 + 1)}{2} = \frac{15 \times 16}{2} = 120.
\]
Step 3: Conclusion.
The number of genotypes possible for this VNTR locus is \( \boxed{120} \).
In a practical examination, the following pedigree chart was given as a spotter for identification. The students identify the given pedigree chart as 
Identify the taxa that constitute a paraphyletic group in the given phylogenetic tree.

The vector, shown in the figure, has promoter and RBS sequences in the 300 bp region between the restriction sites for enzymes X and Y. There are no other sites for X and Y in the vector. The promoter is directed towards the Y site. The insert containing only an ORF provides 3 fragments after digestion with both enzymes X and Y. The ORF is cloned in the correct orientation in the vector using the single restriction enzyme Y. The size of the largest fragment of the recombinant plasmid expressing the ORF upon digestion with enzyme X is ........... bp. (answer in integer) 
Which of the following is/are CORRECT for the two molecules shown? 