Question:

A uniform magnetic field \(\overrightarrow{B}=B_0\hat{z}\), where \(B_0\gt0\) exists as shown in the figure. A charged particle of mass m and charge \(q(q\gt0)\) is released at the origin, in the yz-plane, with a velocity \(\overrightarrow v\) directed at an angle \(\theta\)= 45° with respect to the positive z-axis. Ignoring gravity, which one of the following is TRUE.
A uniform magnetic field B=B0z

Updated On: Oct 1, 2024
  • The initial acceleration \(\overrightarrow a=\frac{qvB_0}{\sqrt 2m}\hat x\)
  • The initial acceleration \(\overrightarrow a=\frac{qvB_0}{\sqrt 2m}\hat y\)
  • The particle moves in a circular path
  • The particle continues in a straight line with constant speed
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The Correct Option is A

Solution and Explanation

The correct answer is (A) : The initial acceleration \(\overrightarrow a=\frac{qvB_0}{\sqrt 2m}\hat x\)
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