A tuple named subject stores the names of different subjects. Write the Python commands to convert the given tuple to a list and thereafter delete the last element of the list.
# Given tuple subject = ("Mathematics", "Physics", "Chemistry", "Biology") # Step 1: Convert the tuple to a list subject_list = list(subject) # Step 2: Delete the last element of the list subject_list.pop() # Resulting list print(subject_list) # Output: ['Mathematics', 'Physics', 'Chemistry']Explanation: A tuple named
subject
is given, which stores the names of different subjects.
To convert the tuple to a list, the list()
function is used: subject_list = list(subject)
.
The pop()
method is then used to remove the last element of the list: subject_list.pop()
.
The resulting list contains all elements of the tuple except the last one.
Example:
Input tuple: ("Mathematics", "Physics", "Chemistry", "Biology") Resulting list: ['Mathematics', 'Physics', 'Chemistry']
Write a user-defined function in Python named showGrades(S) which takes the dictionary S
as an argument. The dictionary S
contains Name: [Eng, Math, Science] as key:value pairs.
The function displays the corresponding grade obtained by the students according to the following grading rules:
\[ \begin{array}{|c|c|} \hline \textbf{Average of Eng, Math, Science} & \textbf{Grade} \\ \hline \geq 90 & A \\ \hline < 90 \text{ but } \geq 60 & B \\ \hline < 60 & C \\ \hline \end{array} \]
Example: Consider the following dictionary: \[ S = \{\text{"AMIT"}: [92, 86, 64], \text{"NAGMA"}: [65, 42, 43], \text{"DAVID"}: [92, 90, 88]\} \] The output should be: \[ \text{AMIT} - B \\ \text{NAGMA} - C \\ \text{DAVID} - A \]
myStr[:4]
extracts the first 4 characters, which are "MISS"
.myStr[-5:]
extracts the last 5 characters, which are "SIPPI"
."#"
in between, resulting in "MISS#SIPPI"
.
event = "G20 Presidency@2023"
L = event.split(' ')
print(L[::-2])
The correct IUPAC name of \([ \text{Pt}(\text{NH}_3)_2\text{Cl}_2 ]^{2+} \) is: