event = "G20 Presidency@2023"
L = event.split(' ')
print(L[::-2])
'G20'
'Presidency@2023'
'G20'
'Presidency@2023'
<div class="question">
<strong>Question:</strong> The split() method divides the string "G20 Presidency@2023" into a list of substrings based on spaces, resulting in:
<pre><code>
L = ["G20", "Presidency@2023"]
</code></pre>
The slicing operation L[::-2] works as follows:
<ul>
<li>[::-2] reverses the list and selects every second element.</li>
<li>Starting from the end, L[::-2] picks "G20".</li>
</ul>
Thus, the output is: ['G20'].
</div>
Our parents told us that we must eat vegetables to be healthy. And it turns out, our parents were right! So, what else did our parents tell?
Our parents told us that we must eat vegetables to be healthy.
And it turns out, our parents were right!
So, what else did our parents tell?
def callon(b=20, a=10):
b = b + a
a = b - a
print(b, "#", a)
return b
x = 100
y = 200
x = callon(x, y)
print(x, "@", y)
y = callon(y)
print(x, "@", y)
A tuple named subject stores the names of different subjects. Write the Python commands to convert the given tuple to a list and thereafter delete the last element of the list.
Write a user-defined function in Python named showGrades(S) which takes the dictionary S as an argument. The dictionary S contains Name: [Eng, Math, Science] as key:value pairs.
The function displays the corresponding grade obtained by the students according to the following grading rules:
\[ \begin{array}{|c|c|} \hline \textbf{Average of Eng, Math, Science} & \textbf{Grade} \\ \hline \geq 90 & A \\ \hline < 90 \text{ but } \geq 60 & B \\ \hline < 60 & C \\ \hline \end{array} \]
Example: Consider the following dictionary: \[ S = \{\text{"AMIT"}: [92, 86, 64], \text{"NAGMA"}: [65, 42, 43], \text{"DAVID"}: [92, 90, 88]\} \] The output should be: \[ \text{AMIT} - B \\ \text{NAGMA} - C \\ \text{DAVID} - A \]

