Step 1: Understanding the Question:
This problem deals with line-of-sight (LOS) communication between two antennas of given heights. We need to find the maximum possible separation between them for a signal to be received, taking into account the curvature of the Earth.
Step 2: Key Formula or Approach:
The maximum line-of-sight distance (\(d_{max}\)) between a transmitting antenna of height \(h_T\) and a receiving antenna of height \(h_R\) is the sum of their individual radio horizons. The formula is:
\[ d_{max} = d_T + d_R = \sqrt{2Rh_T} + \sqrt{2Rh_R} \]
where \(R\) is the radius of the Earth. It's important to use consistent units for all quantities. Since the answer is required in km, it's convenient to use R in km and the heights in km.
Step 3: Detailed Explanation:
Given values:
Height of transmitting antenna, \(h_T = 320 \text{ m} = 0.32 \text{ km}\).
Height of receiving antenna, \(h_R = 2000 \text{ m} = 2.0 \text{ km}\).
Radius of Earth, \(R = 6400 \text{ km}\).
Now, let's calculate the radio horizon for each antenna.
Radio horizon for transmitting antenna:
\[ d_T = \sqrt{2Rh_T} = \sqrt{2 \times 6400 \text{ km} \times 0.32 \text{ km}} \]
\[ d_T = \sqrt{12800 \times 0.32} = \sqrt{4096} = 64 \text{ km} \]
Radio horizon for receiving antenna:
\[ d_R = \sqrt{2Rh_R} = \sqrt{2 \times 6400 \text{ km} \times 2.0 \text{ km}} \]
\[ d_R = \sqrt{12800 \times 2} = \sqrt{25600} = 160 \text{ km} \]
The maximum line-of-sight distance is the sum of these two distances:
\[ d_{max} = d_T + d_R = 64 \text{ km} + 160 \text{ km} = 224 \text{ km} \]
Step 4: Final Answer:
The value of 'd' is 224 km.