A train running at a certain speed crosses a platform in $30$ seconds. What is the speed of the train?
I. Length of the train is $240$ m.
II. The train crosses a man who is on the platform in $12$ seconds.
When a train "crosses a platform", use $(L+P)/v$; when it “crosses a man”, use $L/v$. Often, length + one more time measurement together fix the speed.
If I + II together are necessary to answer the question.
Let train length $L$, platform length $P$, speed $v$. From the stem, \[ \frac{L+P}{v}=30. \tag{1} \] I alone: $L=240$ gives two unknowns ($P,v$) in (1) $\Rightarrow$ not sufficient.
II alone: time to cross a man $=\dfrac{L}{v}=12 \Rightarrow v=\dfrac{L}{12}$, but $L$ unknown $\Rightarrow$ not sufficient.
I + II: from II, $v=L/12$; with $L=240$, $v=20$ m/s. So speed is determined. Hence (e).
In the two triangles, what is the value of \( P + Q + R + S \)?
I. \( A + B = 90^\circ \)
II. \( P + Q = R + S \)
Find the missing code:
L1#1O2~2, J2#2Q3~3, _______, F4#4U5~5, D5#5W6~6
Find the missing number in the table.