A train is moving slowly on a straight track with a constant speed of $2\, ms^{-1}$ passenger in that train starts walking at a steady speed of $2\, ms^{-1}$ to the back of the train in the opposite direction of the motion of the train. So to an observer standing on the platform directly in front of that passenger, the velocity of the passenger appears to be
- $2 \,ms^{-1}$ in the opposite direction of the train.
- zero
- $4\, ms^{-1}$
- $2 \,ms^{-1}$
The Correct Option is B
Solution and Explanation
$=v_{\text {passenger }}-v_{\text {train }}=2-2=0$
$\therefore$ Relative velocity of the passenger w.r.t. the observer is zero.
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.