Question:
A tin chloride Q undergoes the following reactions (not balanced)
$Q+Cl^{-} \to X$
$Q+Me_{3}N \to Y$
$Q+CuCl_{2} \to Z+CuCl$
X is a monoanion having pyramidal geometry. Both Y and Z are neutral compounds. Choose the correct option(s)
A tin chloride Q undergoes the following reactions (not balanced)
$Q+Cl^{-} \to X$
$Q+Me_{3}N \to Y$
$Q+CuCl_{2} \to Z+CuCl$
X is a monoanion having pyramidal geometry. Both Y and Z are neutral compounds. Choose the correct option(s)
Updated On: Jun 14, 2022
- The central atom in $X$ is $sp^3$ hybridized
- There is a coordinate bond in Y
- The oxidation state of the central atom in $Z$ is $+2$
- The central atom in Z has one lone pair of electrons
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The Correct Option is B
Solution and Explanation
Compound Q is $SnCl_2$. The given reactions are
${ $\underset{\text{}}{{SnCl2}}$ + Cl- -> $\underset{\text{(X)}}{{SnCl^{-}_3}}$ }$
${ $\underset{\text{}}{{SnCl2}}$ + Me3N -> $\underset{\text{(Y)}}{{Me3N+ - Sn^{-}Cl2}}$ }$
${ $\underset{\text{}}{{SnCl2}}$ + 2CuCl2 -> $\underset{\text{(Z)}}{{SnCl4 + 2CuCl}}$ }$
Hybridisation of Sn in $SnCl^{-}_{3}$ is $sp^3$
Trimethylamine forms a co-ordinate bond with Sn in $SnCl_2$.
There is no lone pair on central atom of $SnCl_4(Z)$.
${ $\underset{\text{}}{{SnCl2}}$ + Cl- -> $\underset{\text{(X)}}{{SnCl^{-}_3}}$ }$
${ $\underset{\text{}}{{SnCl2}}$ + Me3N -> $\underset{\text{(Y)}}{{Me3N+ - Sn^{-}Cl2}}$ }$
${ $\underset{\text{}}{{SnCl2}}$ + 2CuCl2 -> $\underset{\text{(Z)}}{{SnCl4 + 2CuCl}}$ }$
Hybridisation of Sn in $SnCl^{-}_{3}$ is $sp^3$
Trimethylamine forms a co-ordinate bond with Sn in $SnCl_2$.
There is no lone pair on central atom of $SnCl_4(Z)$.
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