
List-I | List-II | ||
| (P) | At t=0.2s, the magnitude of induced emf in volt | (1) | 0.08 |
| (Q) | At t=0.2s, the magnitude of magnetic force in N | (2) | 0.14 |
| (R) | At t=0.2s, the power dissipated at heat in watt | (3) | 1.20 |
| (S) | The magnitude terminal velocity of the rod in ms\(^{-1}\) | (4) | 0.12 |
| (5) | 2.00 |
| P | Q | R | S |
| 4 | 3 | 2 | 1 |
| P | Q | R | S |
| 2 | 1 | 3 | 4 |
| P | Q | R | S |
| 3 | 4 | 2 | 5 |
| P | Q | R | S |
| 4 | 3 | 1 | 2 |
magnetic force = i ℓ ℓ B = 0.12 N And power dissipated = 0.144 W Also, Terminal velocity = 2 m/s
The correct answer is (C): (P)3 (Q)4 (R)2 (S)5

As shown in the figures, a uniform rod $ OO' $ of length $ l $ is hinged at the point $ O $ and held in place vertically between two walls using two massless springs of the same spring constant. The springs are connected at the midpoint and at the top-end $ (O') $ of the rod, as shown in Fig. 1, and the rod is made to oscillate by a small angular displacement. The frequency of oscillation of the rod is $ f_1 $. On the other hand, if both the springs are connected at the midpoint of the rod, as shown in Fig. 2, and the rod is made to oscillate by a small angular displacement, then the frequency of oscillation is $ f_2 $. Ignoring gravity and assuming motion only in the plane of the diagram, the value of $\frac{f_1}{f_2}$ is:
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Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80
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