To determine the order of wavelengths from shortest to longest for the given types of electromagnetic waves, we need to first understand the general spectrum of electromagnetic radiation. The electromagnetic spectrum, ordered from shortest wavelength to longest, is as follows:
Based on this electromagnetic spectrum, we can arrange the given electromagnetic waves in the order of increasing wavelength:
This sequence corresponds to the option: \(\lambda_1<\lambda_2<\lambda_3<\lambda_4\)
Hence, the correct answer is: \(\lambda_1<\lambda_2<\lambda_3<\lambda_4\)
To determine the ascending order of wavelengths for the given types of electromagnetic waves, we need to understand their relative positions in the electromagnetic spectrum. The electromagnetic spectrum is a range of all types of electromagnetic radiation, organized by their wavelengths or frequencies.
Based on the above information, we can arrange these in ascending order of their wavelengths:
| Type of Radiation | Order in Spectrum |
|---|---|
| Gamma rays (\(\lambda_1\)) | Shortest wavelength |
| X-rays (\(\lambda_2\)) | Next shortest wavelength |
| Infrared waves (\(\lambda_3\)) | Middle wavelengths |
| Microwaves (\(\lambda_4\)) | Longest wavelength |
The correct ascending order of their wavelengths is: \(\lambda_1<\lambda_2<\lambda_3<\lambda_4\)
Therefore, the correct answer is the third option: \( \lambda_1<\lambda_2<\lambda_3<\lambda_4 \).

Given below are two statements:
Statement (I):
are isomeric compounds.
Statement (II):
are functional group isomers.
In the light of the above statements, choose the correct answer from the options given below:
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]