To analyze this system, we need to determine whether it is casual and stable.
- A casual system is one where the output at any time $n$ depends only on present and past values of the input. Since the difference equation defines $y(n)$ in terms of $x(-n)$ (a future value of the input), this system is non-casual.
- A stable system is one where bounded input always produces a bounded output. In this case, the system is stable because the output remains bounded as long as the input is bounded, despite being non-casual.
Therefore, the system is non-casual but stable.