Let the sum be \( P \) and the rate of interest be \( R \) % per annum. The simple interest for 3 years is given by the formula:
\[
\text{Simple Interest (SI)} = \frac{P \times R \times T}{100}
\]
Where:
- \( P \) is the principal amount,
- \( R \) is the rate of interest,
- \( T \) is the time in years.
Given:
- \( T = 3 \) years,
- The increase in interest is Rs.5,100 when the rate is increased by 1% (from \( R \) to \( R+1 \)).
So, the difference in interest is:
\[
\text{Difference in interest} = \frac{P \times (R + 1) \times 3}{100} - \frac{P \times R \times 3}{100} = 5100
\]
\[
\frac{P \times 3}{100} = 5100
\]
\[
P = \frac{5100 \times 100}{3} = 1,70,000
\]
Step 2: Final Answer
The correct answer is (b) Rs.1,70,000.
Final Answer: The correct answer is (b) Rs.1,70,000.