Let the principal amount be \( P \) and the rate of interest be \( r \) percent per annum.
The formula for simple interest is:
\[
\text{SI} = \frac{P \times r \times t}{100}
\]
where:
- \( P \) is the principal,
- \( r \) is the rate of interest,
- \( t \) is the time in years.
We are told that if the rate of interest had been increased by 1%, the interest would have been ₹5,100 more. This means that the difference in interest due to the 1% increase in rate over 3 years is ₹5,100.
Thus, the difference in interest is:
\[
\frac{P \times (r + 1) \times 3}{100} - \frac{P \times r \times 3}{100} = 5100
\]
Simplifying the above equation:
\[
\frac{P \times 3}{100} \times (r + 1 - r) = 5100
\]
\[
\frac{3P}{100} = 5100
\]
\[
3P = 5100 \times 100
\]
\[
3P = 510000
\]
\[
P = \frac{510000}{3} = 170000
\]
Thus, the sum is ₹1,70,000.
The correct answer is (2) ₹1,70,000.