Let number of 10 paise coins be and number of 25 paise coins be\((180-x)\)
\(\frac{1}{10} \times (x) + \frac{1}{4} \times (180 - x) = 36.90 \\\)
\(\Rightarrow \frac{x}{10} - \frac{x}{4} + 45 = 36.90 \\\)
\(\Rightarrow \frac{3x}{20} = 8.10 \\\)
\(\Rightarrow x = 8.10 \times \frac{20}{3} = 54\)
The correct answer is (B) :54 of 10p coins and 126 of 25p coins
Directions: In Question Numbers 19 and 20, a statement of Assertion (A) is followed by a statement of Reason (R).
Choose the correct option from the following:
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
(C) Assertion (A) is true, but Reason (R) is false.
(D) Assertion (A) is false, but Reason (R) is true.
Assertion (A): For any two prime numbers $p$ and $q$, their HCF is 1 and LCM is $p + q$.
Reason (R): For any two natural numbers, HCF × LCM = product of numbers.