Let number of 10 paise coins be and number of 25 paise coins be\((180-x)\)
\(\frac{1}{10} \times (x) + \frac{1}{4} \times (180 - x) = 36.90 \\\)
\(\Rightarrow \frac{x}{10} - \frac{x}{4} + 45 = 36.90 \\\)
\(\Rightarrow \frac{3x}{20} = 8.10 \\\)
\(\Rightarrow x = 8.10 \times \frac{20}{3} = 54\)
The correct answer is (B) :54 of 10p coins and 126 of 25p coins