
\[ \text{Total from S} = 200 \ \text{villages} \times 50 \ \text{kids per village} = 10{,}000 \]
Given: 60% of kids in S are in government schools: \[ \text{Kids in G} = 60\% \times 10{,}000 = 6{,}000 \]
Given: 37% of total surveyed kids in S are in private schools: \[ \text{Kids in P} = 37\% \times 10{,}000 = 3{,}700 \]
\[ \text{Percentage} = \frac{\text{Kids in P from S}}{\text{Total kids from S}} \times 100 \] \[ = \frac{3{,}700}{10{,}000} \times 100 = 37\% \]
\[ \boxed{\text{37\%}} \]
To find the number of kids in the West (W) whose mothers had completed primary education and who were not in school, follow these steps:
| Region | G | P | O |
|---|---|---|---|
| W | X | Y | Z |
The number of kids in W whose mothers completed primary education and are not in school is 300.
Let's break down the information provided to determine the number of surveyed kids now in G in W (the West).
First, we calculate the total number of surveyed kids and their distribution:
Calculating kids in W during the initial survey:
Two years later, all kids were in school with additional info:
Total in G in W now = previous G(W) + new G additions:
Thus, based on the information, the correct value is not among the original provided options. Kindly check with the re-evaluated calculations: Total G(W) is now 7375.
To solve this problem, we need to analyze the information given and make deductions based on the percentages of kids joining different schools over the years. The key points are:
Initially, let's compute the number of surveyed children initially who are 'O':
Now, look at the final distributions:
| Region | Initial O Fraction | G Now |
|---|---|---|
| NE | 7500*0.08 | (same as in W) |
| W | 12500*0.08 | (same as in NE) |
| S | 10000*0.08 = 800 | 0.75*800 joined G |
The survey stats reveal that 94.7% of S's surveyed kids had mothers who didn't complete primary school and were in G, as calculated:
Given data sum and interpretations correctly, we reach the solution: 94.7% as per available information, so the correct answer option is 94.7%.
A train travels from Station A to Station E, passing through stations B, C, and D, in that order. The train has a seating capacity of 200. A ticket may be booked from any station to any other station ahead on the route, but not to any earlier station. A ticket from one station to another reserves one seat on every intermediate segment of the route. For example, a ticket from B to E reserves a seat in the intermediate segments B– C, C– D, and D–E. The occupancy factor for a segment is the total number of seats reserved in the segment as a percentage of the seating capacity. The total number of seats reserved for any segment cannot exceed 200. The following information is known. 1. Segment C– D had an occupancy factor of 952. Exactly 40 tickets were booked from B to C and 30 tickets were booked from B to E. 3. Among the seats reserved on segment D– E, exactly four-sevenths were from stations before C. 4. The number of tickets booked from A to C was equal to that booked from A to E, and it was higher than that from B to E. 5. No tickets were booked from A to B, from B to D and from D to E. 6. The number of tickets booked for any segment was a multiple of 10.