Comprehension
A student placed a candle flame at different distances from a convex lens and focused its image on a screen. He recorded his observation in tabular form as given below:
A student placed a candle flame at different distances from a convex lens and focused its image
Question: 1

What is the focal length of the convex lens used? Give reason to justify your answer.

Show Hint

The focal length of a convex lens is positive and can be calculated using the lens formula with object and image distances.
Updated On: May 19, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

(a) Focal Length of the Convex Lens:
We will calculate the focal length using the lens formula: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] where:
- \( f \) is the focal length,
- \( v \) is the image distance,
- \( u \) is the object distance.
We will consider two observations to calculate the focal length. Observation 1: Object distance \( u = -60 \, \text{cm}, \, v = +20 \, \text{cm} \) Using the lens formula: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{20} - \frac{1}{-60} \] \[ \frac{1}{f} = \frac{1}{20} + \frac{1}{60} = \frac{3}{60} = \frac{1}{20} \] Thus, the focal length is: \[ f = 20 \, \text{cm} \] Observation 2: Object distance \( u = -40 \, \text{cm}, \, v = +24 \, \text{cm} \) Using the lens formula: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{24} - \frac{1}{-40} \] \[ \frac{1}{f} = \frac{1}{24} + \frac{1}{40} = \frac{5}{120} = \frac{1}{24} \] Thus, the focal length is: \[ f = 24 \, \text{cm} \] The average of the focal lengths from the two observations is: \[ f_{\text{avg}} = \frac{20 + 24}{2} = 22 \, \text{cm} \] Thus, the focal length of the convex lens is approximately \( \boxed{22 \, \text{cm}} \).
Was this answer helpful?
0
0
Question: 2

Which one of the sets of observations is not correct and why?

Show Hint

In convex lenses, as the object distance decreases, the image distance increases for real and inverted images.
Updated On: May 19, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

Let us analyze the data provided:
Let us analyze the data provided
The object distances are all negative (since the object is placed on the left side of the lens), and the image distances are positive, indicating the formation of a real and inverted image. We observe the following trend: As the object distance becomes smaller (i.e., as the object approaches the lens), the image distance increases. This is the expected behavior for a convex lens, where the image distance should increase as the object distance decreases. The pattern follows the general trend, except for the following observation:
- When the object is at a distance of -24 cm, the image distance is +40 cm.
- However, when the object is at -20 cm, the image distance increases to +60 cm, which is expected. Thus, the set where the object distance is -24 cm and the image distance is +40 cm does not align with the general rate of change between object and image distances. Conclusion: The observation set with the object at -24 cm and the image at +40 cm is not correct because it does not follow the expected pattern of increasing image distance with decreasing object distance.
Was this answer helpful?
0
0
Question: 3

Draw Ray Diagram to show Image Formation for any correct set of observation.

Show Hint

In ray diagrams for convex lenses, parallel rays converge at the focal point on the opposite side of the lens, forming real and inverted images.
Updated On: May 19, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

A ray diagram for a convex lens will show how light rays from the object (candle flame) pass through the lens and form an image on the screen. In this case, for object distances such as -60 cm and -40 cm, the rays converge on the other side of the lens to form a real and inverted image. A ray diagram for any set of observations, such as when the object is placed at a distance of -60 cm from the lens, is as follows:
1. Draw a convex lens in the center.
2. Mark the focal point (F) on both sides of the lens.
3. Draw the object (the candle flame) to the left of the lens.
4. Draw two light rays from the object: one parallel to the principal axis, which refracts through the focal point on the opposite side, and the other passing through the center of the lens without bending.
5. The point where the refracted rays meet is where the image is formed on the screen.
Was this answer helpful?
0
0

Questions Asked in CBSE X exam

View More Questions