Step 1: Calculate the number of pixels at 600 dpi.
- Resolution = 600 dpi $\Rightarrow$ in 10 inches, number of dots = $10 \times 600 = 6000$.
- So, image size = $6000 \times 6000 = 36,000,000$ pixels.
Step 2: Calculate the number of pixels at 300 dpi.
- Resolution = 300 dpi $\Rightarrow$ in 10 inches, number of dots = $10 \times 300 = 3000$.
- So, image size = $3000 \times 3000 = 9,000,000$ pixels.
Step 3: Percentage reduction.
\[
\text{Reduction} = \frac{\text{Initial pixels} - \text{Final pixels}}{\text{Initial pixels}} \times 100
\]
\[
= \frac{36,000,000 - 9,000,000}{36,000,000} \times 100
= \frac{27,000,000}{36,000,000} \times 100
= 75%
\]
\[
\boxed{75%}
\]
The figures, I, II, and III are parts of a sequence. Which one of the following options comes next in the sequence as IV?
For the beam and loading shown in the figure, the second derivative of the deflection curve of the beam at the mid-point of AC is given by \( \frac{\alpha M_0}{8EI} \). The value of \( \alpha \) is ........ (rounded off to the nearest integer).