Question:

A student has to answer 10 questions, choosing at least 4 from each of the parts A and B. If there are 6 questions in part A and 7 in part B, then the number of ways can the student choose 10 questions is

Updated On: Apr 1, 2025
  • 256
  • 352
  • 266
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The Correct Option is C

Solution and Explanation

The student needs to choose 10 questions, at least 4 from part A and 4 from part B. Let’s break down the selection process:

  • There are 6 questions in part A and 7 questions in part B.
  • The student must choose at least 4 questions from part A and at least 4 questions from part B. Therefore, the student must choose either 4, 5, or 6 questions from part A, and the remaining questions will be from part B.

We will now calculate the number of ways the student can choose questions:
1. Choose 4 questions from part A and 6 questions from part B: \[ \text{Ways} = \binom{6}{4} \times \binom{7}{6} = 15 \times 7 = 105 \]
2. Choose 5 questions from part A and 5 questions from part B: \[ \text{Ways} = \binom{6}{5} \times \binom{7}{5} = 6 \times 21 = 126 \]
3. Choose 6 questions from part A and 4 questions from part B: \[ \text{Ways} = \binom{6}{6} \times \binom{7}{4} = 1 \times 35 = 35 \] Now, add up all the possibilities: \[ \text{Total ways} = 105 + 126 + 35 = 266 \]

The correct answer is (C) : 266.

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