Question:

A straight line meets the coordinates axes at $A$ and $B$, so that the centroid of the triangle $OAB\, is \, (1, 2)$. Then the equation of the line $AB$ is

Updated On: May 11, 2024
  • $x + y = 6$
  • $2x + y = 6$
  • $x +2y = 6$
  • $3x + y = 6$
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The Correct Option is B

Solution and Explanation

Since straight line meets the coordinate axes at A and B, so equation of line in intercept from is $\frac{x}{a} + \frac{y}{b} = 1$

$\therefore \:\: G \left( \frac{ 0 + a + 0}{3} , \frac{0 +0 +b}{3} \right) = (1,2)$ (given)
$\Rightarrow \:\: \frac{a}{3} = 1 \Rightarrow \:\: a = 3, \frac{b}{3} = 2 \: \Rightarrow \: b = 6$
Hence, required equation of line is
$ \frac{x}{3} + \frac{y}{6} = 1 \Rightarrow \:\: 2x + y = 6$

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Concepts Used:

Straight lines

A straight line is a line having the shortest distance between two points. 

A straight line can be represented as an equation in various forms,  as show in the image below:

 

The following are the many forms of the equation of the line that are presented in straight line-

1. Slope – Point Form

Assume P0(x0, y0) is a fixed point on a non-vertical line L with m as its slope. If P (x, y) is an arbitrary point on L, then the point (x, y) lies on the line with slope m through the fixed point (x0, y0) if and only if its coordinates fulfil the equation below.

y – y0 = m (x – x0)

2. Two – Point Form

Let's look at the line. L crosses between two places. P1(x1, y1) and P2(x2, y2)  are general points on L, while P (x, y) is a general point on L. As a result, the three points P1, P2, and P are collinear, and it becomes

The slope of P2P = The slope of P1P2 , i.e.

\(\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\)

Hence, the equation becomes:

y - y1 =\( \frac{y_2-y_1}{x_2-x_1} (x-x1)\)

3. Slope-Intercept Form

Assume that a line L with slope m intersects the y-axis at a distance c from the origin, and that the distance c is referred to as the line L's y-intercept. As a result, the coordinates of the spot on the y-axis where the line intersects are (0, c). As a result, the slope of the line L is m, and it passes through a fixed point (0, c). The equation of the line L thus obtained from the slope – point form is given by

y – c =m( x - 0 )

As a result, the point (x, y) on the line with slope m and y-intercept c lies on the line, if and only if

y = m x +c