The principle of conservation of momentum and conservation of energy is applied to solve the problem.
The total initial momentum is equal to the total final momentum, and the total initial energy is equal to the total final energy.
Let the kinetic energy of \( {}^{17}_{8}O \) be \( K_{{}^{17}_{8}O} \). From conservation of momentum, the momentum of the particles is related to their kinetic energy \( K \) as:
\[ p = \sqrt{2mK} \]
where \( m \) is the mass of the particle.
For \( {}^{17}_{8}O \) and \( {}^{1}_{1}H \), the relationship between their momenta can be written as:
\[ p_{{}^{17}_{8}O} = - p_{{}^{1}_{1}H} \]
The total kinetic energy is given as:
\[ K_{\text{total}} = K_{{}^{4}_{2}He} + K_{{}^{14}_{7}N} = K_{{}^{17}_{8}O} + K_{{}^{1}_{1}H} \]
Substituting the given values:
\[ 5.314 + 0 = K_{{}^{17}_{8}O} + 4.012 \]
Solving for \( K_{{}^{17}_{8}O} \):
\[ K_{{}^{17}_{8}O} = 5.314 - 4.012 = 1.302 \text{ MeV} \]
The masses of the particles influence the kinetic energy distribution. Using the mass ratio correction:
\[ K_{{}^{17}_{8}O} = \frac{m_{{}^{1}_{1}H}}{m_{{}^{17}_{8}O}} K_{{}^{1}_{1}H} \]
Substituting \( m_{{}^{1}_{1}H} = 1.008u \) and \( m_{{}^{17}_{8}O} = 16.999u \):
\[ K_{{}^{17}_{8}O} = \frac{1.008}{16.999} \times 4.012 \]
\[ K_{{}^{17}_{8}O} \approx 0.400 \text{ MeV} \]
The corrected kinetic energy of \( {}^{17}_{8}O \) is approximately 0.400 MeV.
The motion of a particle in the XY plane is given by \( x(t) = 25 + 6t^2 \, \text{m} \); \( y(t) = -50 - 20t + 8t^2 \, \text{m} \). The magnitude of the initial velocity of the particle, \( v_0 \), is given by:
The P-V diagram of an engine is shown in the figure below. The temperatures at points 1, 2, 3 and 4 are T1, T2, T3 and T4, respectively. 1β2 and 3β4 are adiabatic processes, and 2β3 and 4β1 are isochoric processes
Identify the correct statement(s).
[Ξ³ is the ratio of specific heats Cp (at constant P) and Cv (at constant V)]