Step 1: Calculate the mass of ethyl alcohol and water
\[ \text{Mass of ethyl alcohol} = 1 \, \text{mole} \times 46 \, \text{g mol}^{-1} = 46 \, \text{g}. \]
\[ \text{Mass of water} = 9 \, \text{mole} \times 18 \, \text{g mol}^{-1} = 162 \, \text{g}. \]
Step 2: Calculate total mass of solution
\[ \text{Total mass of solution} = \text{Mass of ethyl alcohol} + \text{Mass of water} = 46 + 162 = 208 \, \text{g}. \]
Step 3: Calculate mass percent of ethyl alcohol
\[ \text{Mass percent of ethyl alcohol} = \frac{\text{Mass of ethyl alcohol}}{\text{Total mass of solution}} \times 100. \]
\[ \text{Mass percent} = \frac{46}{208} \times 100 = 22.11\%. \]
Final Answer: 22
According to the generally accepted definition of the ideal solution there are equal interaction forces acting between molecules belonging to the same or different species. (This is equivalent to the statement that the activity of the components equals the concentration.) Strictly speaking, this concept is valid in ecological systems (isotopic mixtures of an element, hydrocarbons mixtures, etc.). It is still usual to talk about ideal solutions as limiting cases in reality since very dilute solutions behave ideally with respect to the solvent. This law is further supported by the fact that Raoult’s law empirically found for describing the behaviour of the solvent in dilute solutions can be deduced thermodynamically via the assumption of ideal behaviour of the solvent.
Answer the following questions:
(a) Give one example of miscible liquid pair which shows negative deviation from Raoult’s law. What is the reason for such deviation?
(b) (i) State Raoult’s law for a solution containing volatile components.
OR
(ii) Raoult’s law is a special case of Henry’s law. Comment.
(c) Write two characteristics of an ideal solution.