A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity $v\, m/s$. If it is to climb the inclined surface then $v$ should be
- $\geq \sqrt{\frac{10}{7} g h}$
- $\ge\sqrt{2gh}$
- $2gh$
- $\frac{10}{7} g h$
The Correct Option is A
Solution and Explanation
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- Transcription
Concepts Used:
System of Particles and Rotational Motion
- The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
- The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
- The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.