Given:
Mass of the cube \( m \)
Initial temperature of the cube \( \theta_0 \)
Final temperature to become liquid \( \theta_1 \)
Final temperature to become vapour \( \theta_2 \)
Specific heat in the solid state \( s_1 \)
Specific heat in the liquid state \( s_2 \)
Latent heat of fusion \( L_f \)
Latent heat of vaporisation \( L_v \) The minimum heat energy required to heat the cube from its initial state to the point where it turns into vapour consists of the following stages: 1. Heating the solid cube from temperature \( \theta_0 \) to \( \theta_1 \): The heat required for this stage is: \[ Q_1 = m s_1 (\theta_1 - \theta_0) \] 2. Melting the cube from solid to liquid at temperature \( \theta_1 \): The heat required for this stage is the latent heat of fusion: \[ Q_2 = m L_f \] 3. Heating the liquid from temperature \( \theta_1 \) to \( \theta_2 \): The heat required for this stage is: \[ Q_3 = m s_2 (\theta_2 - \theta_1) \] 4. Vaporising the liquid at temperature \( \theta_2 \): The heat required for this stage is the latent heat of vaporisation: \[ Q_4 = m L_v \] Total heat energy required: The total heat energy supplied to the cube is the sum of all these stages: \[ Q_{\text{total}} = m s_1 (\theta_1 - \theta_0) + m L_f + m s_2 (\theta_2 - \theta_1) + m L_v \] Thus, the minimum heat energy supplied to the cube until it vaporises is: \[ Q_{\text{total}} = m s_1 (\theta_1 - \theta_0) + m L_f + m s_2 (\theta_2 - \theta_1) + m L_v \] Therefore, the correct answer is (C): \( m s_1 (\theta_1 - \theta_0) + m L_f + m s_2 (\theta_2 - \theta_1) + m L_v \).