To determine increasing or decreasing intervals, we first find the first derivative \( f'(x) \).
Step 1: Compute \( f'(x) \) using the product rule.
Given: \[ f(x) = e^x \sin x. \] Using the product rule: \[ f'(x) = \frac{d}{dx} (e^x \sin x) = e^x \frac{d}{dx} (\sin x) + \sin x \frac{d}{dx} (e^x). \] \[ f'(x) = e^x \cos x + e^x \sin x. \] \[ f'(x) = e^x (\cos x + \sin x). \]
Step 2: Find the critical points.
To find critical points, set \( f'(x) = 0 \): \[ e^x (\cos x + \sin x) = 0. \] Since \( e^x>0 \) for all \( x \), we set: \[ \cos x + \sin x = 0. \] Dividing both sides by \( \cos x \): \[ 1 + \tan x = 0. \] \[ \tan x = -1. \] Solving in \( [0, \pi] \): \[ x = \frac{3\pi}{4}. \]
Step 3: Determine sign changes in \( f'(x) \).
For \( x \in [0, \pi] \), check the sign of \( f'(x) \) in the intervals:
1. \( (0, \frac{3\pi}{4}) \): Choose \( x = \frac{\pi}{2} \). \[ \cos \frac{\pi}{2} + \sin \frac{\pi}{2} = 0 + 1 = 1>0. \] So, \( f'(x)>0 \), meaning \( f(x) \) is increasing.
2. \( (\frac{3\pi}{4}, \pi) \): Choose \( x = \pi \). \[ \cos \pi + \sin \pi = -1 + 0 = -1<0. \] So, \( f'(x)<0 \), meaning \( f(x) \) is decreasing.
Final Answer:
- \( f(x) \) is increasing for \( x \in (0, \frac{3\pi}{4}) \).
- \( f(x) \) is decreasing for \( x \in (\frac{3\pi}{4}, \pi) \).
Step 1: Compute the second derivative \( f''(x) \).
Using the derivative \( f'(x) = e^x (\cos x + \sin x) \), apply the product rule again: \[ f''(x) = e^x (\cos x + \sin x) + e^x (\cos x - \sin x). \] \[ = e^x [(\cos x + \sin x) + (\cos x - \sin x)]. \] \[ = e^x (2\cos x). \] Step 2: Evaluate \( f''(x) \) at the critical point \( x = \frac{3\pi}{4} \).
\[ f''\left(\frac{3\pi}{4}\right) = e^{3\pi/4} (2\cos (3\pi/4)). \] Since: \[ \cos(3\pi/4) = -\frac{1}{\sqrt{2}}, \] \[ f''(3\pi/4) = e^{3\pi/4} \left(2 \times -\frac{1}{\sqrt{2}}\right). \] \[ = -e^{3\pi/4} \sqrt{2}. \] Since \( f''(3\pi/4)<0 \), the function has a local maximum at \( x = \frac{3\pi}{4} \).
Final Answer:
The critical point \( x = \frac{3\pi}{4} \) is a local maximum.
Find the interval in which $f(x) = x + \frac{1}{x}$ is always increasing, $x \neq 0$.
Rupal, Shanu and Trisha were partners in a firm sharing profits and losses in the ratio of 4:3:1. Their Balance Sheet as at 31st March, 2024 was as follows:
(i) Trisha's share of profit was entirely taken by Shanu.
(ii) Fixed assets were found to be undervalued by Rs 2,40,000.
(iii) Stock was revalued at Rs 2,00,000.
(iv) Goodwill of the firm was valued at Rs 8,00,000 on Trisha's retirement.
(v) The total capital of the new firm was fixed at Rs 16,00,000 which was adjusted according to the new profit sharing ratio of the partners. For this necessary cash was paid off or brought in by the partners as the case may be.
Prepare Revaluation Account and Partners' Capital Accounts.