Question:

A small satellite is revolving near earths surface. Its orbital velocity will be nearly:

Updated On: Jun 7, 2022
  • 11.2 km/sec
  • 6 km/sec
  • 4 km/sec
  • 8 km/sec
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The Correct Option is D

Solution and Explanation

From the formula the orbital velocity near earth is $ =\sqrt{Rg} $ $ =\sqrt{6.4\times {{10}^{6}}\times 10}=8km\text{/}\sec $
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].