Question:
A small object of uniform density rolls up a curved surface with an initial velocity v. It reaches up to a maximum height of $\frac{3v^2}{4g}$ with respect to the initial position. The object is
A small object of uniform density rolls up a curved surface with an initial velocity v. It reaches up to a maximum height of $\frac{3v^2}{4g}$ with respect to the initial position. The object is
Updated On: Mar 14, 2024
- ring
- solid sphere
- hollow sphere
- disc
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The Correct Option is D
Solution and Explanation
$\frac{1}{2}mv^2+\frac{1}{2}I\bigg(\frac{v}{R}\bigg)^2=mg\bigg(\frac{3v^2}{4g}\bigg)$
$\therefore I=\frac{1}{2}mR^2$
$\therefore$ Body is disc. The correct option is (d).
$\therefore I=\frac{1}{2}mR^2$
$\therefore$ Body is disc. The correct option is (d).
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