A small object of uniform density rolls up a curved surface with an initial velocity v. It reaches up to a maximum height of $\frac{3v^2}{4g}$ with respect to the initial position. The object is
$\frac{1}{2}mv^2+\frac{1}{2}I\bigg(\frac{v}{R}\bigg)^2=mg\bigg(\frac{3v^2}{4g}\bigg)$ $\therefore I=\frac{1}{2}mR^2$ $\therefore$ Body is disc. The correct option is (d).
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