The output voltage in such a case can be calculated using the duty cycle method. For 4 cycles on and 5 cycles off, the duty cycle \( D \) is:
\[
D = \frac{4}{4 + 5} = \frac{4}{9}
\]
The RMS output voltage \( V_{rms} \) is given by:
\[
V_{rms} = V_{in} \times \sqrt{D} = 210 \times \sqrt{\frac{4}{9}} = 210 \times \frac{2}{3} = 140 \text{ V}
\]