Question

A single-phase full bridge inverter is connected to a load of 24 \( \Omega \). The DC input voltage is 48 V. What is the rms output voltage at fundamental frequency?

• A. \( \frac{4 \times 48}{\pi} \, \text{V} \)
• B. \( \frac{2 \times 48}{\sqrt{2}} \, \text{V} \)
• C. \( \frac{4 \times 48}{2\pi} \, \text{V} \)
• D. \( \frac{2 \times 48}{\pi} \, \text{V} \)

Hint:

RMS voltage of fundamental in full bridge inverter = \( \frac{4V_{dc}}{\pi} \)

Answer 1

The Correct Option is A

Step 1: RMS of Fundamental in Full-Bridge Inverter
For square wave inverter output, the fundamental rms value is: \[ V_{rms,1} = \frac{4V_{dc}}{\pi} \] Step 2: Apply Values
\[ V_{dc} = 48V \Rightarrow V_{rms} = \frac{4 \times 48}{\pi} \] Conclusion:
Option (1) is correct.