The current through the ammeter can be extended by adding a shunt resistance in parallel. To extend the range from 100 A to 500 A, we use the formula for parallel resistances:
\[
R_{\text{shunt}} = \frac{R_{\text{ammeter}}}{\text{Range Factor} - 1}
\]
The range factor is \( \frac{500}{100} = 5 \). Thus, the internal resistance of the ammeter is:
\[
R_{\text{ammeter}} = 25 \times (5 - 1) = 100 \, \Omega
\]
Thus, the internal resistance is 100 ohms.
Thus, the correct answer is 100 ohms.