Let the magnetic moment of the short magnetic needle be $\vec{m}$.
The torque ($\vec{\tau}$) experienced by a magnetic needle in a magnetic field ($\vec{B}$) is given by $\vec{\tau} = \vec{m} \times \vec{B}$.
The magnitude of the torque is $\tau = |\vec{m}| |\vec{B}| \sin\theta = mB\sin\theta$, where $\theta$ is the angle between $\vec{m}$ and $\vec{B}$.
When a magnetic needle is "placed" in a field, it will align itself with the field if free to rotate, or experience torque if held at an angle. The question implies it's *placed* and then experiences torque, suggesting it's not initially aligned. "A short magnetic needle is placed in a magnetic field" usually implies it orients to minimize energy, unless an initial orientation is given. If it is simply placed, it will try to align, and if it's slightly disturbed or held, it experiences torque. Let's assume the needle is placed such that its magnetic moment $\vec{m}$ is initially perpendicular to the applied field $\vec{B}$ to experience maximum torque, or the problem implies that $\sin\theta$ part is somehow constant or comparable.
Let's re-interpret "placed in a magnetic field $\vec{B}_i$ in the direction $(\sqrt{3}\hat{i}+\hat{j})$". This could mean the needle itself is oriented along $\vec{B}_i$ (its own internal field direction?) and then subjected to external field in direction $(\sqrt{3}\hat{i}+\hat{j})$. This is very confusing.
Let's assume standard problem setup: "A short magnetic needle with moment $m$ is placed such that it makes an angle $\theta$ with an external field $B_1$..."
The phrase "The needle experiences a torque" means $m B_1 \sin\theta_1 = 0.06$ Nm.
In the second case, $m B_2 \sin\theta_2 = \tau_2$.
Let's assume "placed in a magnetic field $\vec{B}_1$" where $\vec{B}_1$ is the external field vector $B_1 \hat{u}_1$, with $\hat{u}_1$ being the direction $(\sqrt{3}\hat{i}+\hat{j})$. The magnitude is $B_1$.
And "magnetic field $\vec{B}_2$" where $\vec{B}_2$ is $B_2 \hat{u}_2$, with $\hat{u}_2$ being the direction $(\hat{i}+\sqrt{3}\hat{j})$. The magnitude is $B_2$.
The question labels these magnitudes as "$B_i$" and "$2B_j$". If we assume $B_i$ and $B_j$ are just scalar magnitudes and perhaps $B_i=B_j=B_{ref}$, then $|\vec{B}_1| = B_{ref}$ and $|\vec{B}_2| = 2B_{ref}$.
Let the needle's initial orientation (e.g., along x-axis, $\vec{m} = m\hat{i}$) be fixed when subjected to these fields.
Case 1: External field $\vec{B}_1 = B_{ref} \frac{\sqrt{3}\hat{i}+\hat{j}}{|\sqrt{3}\hat{i}+\hat{j}|} = B_{ref} \frac{\sqrt{3}\hat{i}+\hat{j}}{\sqrt{3+1}} = B_{ref} \frac{\sqrt{3}\hat{i}+\hat{j}}{2}$.
Torque $\vec{\tau}_1 = \vec{m} \times \vec{B}_1$. If $\vec{m} = m\hat{i}$:
$\vec{\tau}_1 = m\hat{i} \times B_{ref} \frac{\sqrt{3}\hat{i}+\hat{j}}{2} = m B_{ref} \left( \hat{i} \times \frac{\sqrt{3}}{2}\hat{i} + \hat{i} \times \frac{1}{2}\hat{j} \right) = m B_{ref} (0 + \frac{1}{2}\hat{k}) = \frac{1}{2} m B_{ref} \hat{k}$.
Magnitude $\tau_1 = \frac{1}{2} m B_{ref} = 0.06$ Nm.
Case 2: External field $\vec{B}_2 = 2B_{ref} \frac{\hat{i}+\sqrt{3}\hat{j}}{|\hat{i}+\sqrt{3}\hat{j}|} = 2B_{ref} \frac{\hat{i}+\sqrt{3}\hat{j}}{2} = B_{ref} (\hat{i}+\sqrt{3}\hat{j})$.
Torque $\vec{\tau}_2 = \vec{m} \times \vec{B}_2$. If $\vec{m} = m\hat{i}$:
$\vec{\tau}_2 = m\hat{i} \times B_{ref} (\hat{i}+\sqrt{3}\hat{j}) = m B_{ref} (\hat{i}\times\hat{i} + \hat{i}\times\sqrt{3}\hat{j}) = m B_{ref} (0 + \sqrt{3}\hat{k}) = \sqrt{3} m B_{ref} \hat{k}$.
Magnitude $\tau_2 = \sqrt{3} m B_{ref}$.
From Case 1, $m B_{ref} = 2 \times 0.06 = 0.12$ Nm.
So, $\tau_2 = \sqrt{3} \times (0.12) \text{ Nm} \approx 1.732 \times 0.12 \approx 0.2078$ Nm. This is not among options.
The wording "placed in a magnetic field" often implies the needle is free to align, and then the torque is asked for a *deflection* from this equilibrium, or it's about maximum torque. If maximum torque, $\sin\theta=1$.
Then $\tau_1 = m B_1 = 0.06$ Nm. And $\tau_2 = m B_2$.
If $B_1=B_{ref}$ and $B_2=2B_{ref}$, then $B_2 = 2B_1$.
So $\tau_2 = m (2B_1) = 2 (mB_1) = 2 \times \tau_1 = 2 \times 0.06 = 0.12$ Nm.
This explanation is the simplest and matches option (a). It assumes that the term "direction $(\sqrt{3}\hat{i}+\hat{j})$" is extraneous information or relevant for some other unasked part, and that the crucial parts are the magnitudes of the fields, and that $\sin\theta$ is the same in both cases (e.g. $\theta=90^\circ$ for maximum torque, or the needle is held in the same orientation relative to some fixed axis, and it's the angle with the field that changes).
Let's assume the interpretation that leads to $\tau_2 = 2\tau_1$:
The needle has magnetic moment $m$.
In the first case, it is placed in a field $B_1$ (magnitude $B_i$) and experiences torque $\tau_1 = m B_1 \sin\theta_1 = 0.06$ Nm.
In the second case, it is placed in a field $B_2$ (magnitude $2B_j$).
If we assume $B_i = B_j = B_{magnitude}$, then $B_1 = B_{magnitude}$ and $B_2 = 2B_{magnitude}$. So $B_2 = 2B_1$.
If the orientation factor $\sin\theta$ remains the same (e.g. needle is always placed perpendicular to the field to measure max torque, or its orientation is fixed and the field direction is what changes but the problem is simplified),
then $\tau_2 = m B_2 \sin\theta_2 = m (2B_1) \sin\theta_1 = 2 (m B_1 \sin\theta_1) = 2 \tau_1$.
$\tau_2 = 2 \times 0.06 \text{ Nm} = 0.12 \text{ Nm}$.
This interpretation makes sense for a multiple-choice question leading to a simple answer. The complex vector directions are likely distractors or part of poorly formulated question.
\[ \boxed{0.12 \text{ Nm}} \]