To determine the diameter of the wire, we need to understand the readings given by the screw gauge:
The screw gauge uses two scales: the main scale and the circular scale.
The given data is:
According to the question, \(1\, \text{mm}\) on the main scale corresponds to \(100\) divisions on the circular scale. Therefore, each division on the circular scale corresponds to:
\(\frac{1}{100}\, \text{mm} = 0.01\, \text{mm}\)
Given the circular scale reading is \(52\) divisions, the value it represents in millimeters is:
\(52 \times 0.01\, \text{mm} = 0.52\, \text{mm}\)
Since the main scale reading is \(0\, \text{mm}\), the total reading (which is the diameter of the wire) is solely due to the circular scale:
\(0 + 0.52\, \text{mm} = 0.52\, \text{mm}\)
Converting \(0.52\, \text{mm}\) to centimeters (since the options are in cm):
\(0.52\, \text{mm} = 0.052\, \text{cm}\)
Therefore, the diameter of the wire is \(0.052\, \text{cm}\).
Thus, the correct answer is 0.052 cm.
The elastic behavior of material for linear stress and linear strain, is shown in the figure. The energy density for a linear strain of 5×10–4 is ____ kJ/m3. Assume that material is elastic up to the linear strain of 5×10–4
Three identical heat conducting rods are connected in series as shown in the figure. The rods on the sides have thermal conductivity 2K while that in the middle has thermal conductivity K. The left end of the combination is maintained at temperature 3T and the right end at T. The rods are thermally insulated from outside. In steady state, temperature at the left junction is \(T_1\) and that at the right junction is \(T_2\). The ratio \(T_1 / T_2\) is 
