Question

Which of the following is a list of the sites in an order in which the reporter can visit them, from the first site visited to the last site visited?

• A. Quin, Ram, Sud, Vara, Xilat, Tunin
• B. Quin, Sud, Vara, Tunin, Ram, Xilat
• C. Ram, Sud, Vara, Tunin, Quin, Xilat
• D. Xilat, Ram, Sud, Tunin, Quin, Vara
• E. Xilat, Tunin, Ram, Quin, Sud, Vara
• A. Quin
• B. Sud
• C. Tunin
• D. Vara
• J. Xilat
• A. Quin
• B. Ram
• C. Sud
• D. Vara
• O. Xilat
• A. Quin is visited second.
• B. Ram is visited third.
• C. Sud is visited fourth.
• D. Vara is visited fifth.
• T. Xilat is visited sixth.
• A. Quin is visited at some time after Tunin is visited.
• B. Ram is visited at some time after Quin is visited.
• C. Tunin is visited at some time after Ram is visited.
• D. Tunin is visited at some time after Sud is visited.
• Y. Xilat is visited at some time after Sud is visited.
• A. Quin is the first site visited.
• B. Tunin is the second site visited.
• C. Tunin is the third site visited.
• D. Vara is the sixth site visited.
• ^. Xilat is the sixth site visited.
• A. Quin is the fifth site visited.
• B. Ram is the fifth site visited.
• C. Sud is the second site visited.
• D. Xilat is the second site visited.
• c. Xilat is the fifth site visited.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept:
This question asks for a complete and valid sequence of visits. We can test each option against the rules.
Step 2: Key Formula or Approach:
Use the established rules and deductions to quickly eliminate invalid sequences. - Starts with Q or X? - Ends with V or X? - Is there an SV block? - Is R before S?
Step 3: Detailed Explanation:
- (A) Q, R, S, V, X, T: Starts with Q (ok). Ends with T. Violates Rule 2 (must end with V or X). Invalid.
- (B) Q, S, V, T, R, X: Starts with Q (ok). Ends with X (ok). Contains an SV block (ok). But R is after S. Violates Rule 4 (R...S). Invalid.
- (C) R, S, V, T, Q, X: Starts with R. Violates Rule 1 (must start with Q or X). Invalid.
- (D) X, R, S, T, Q, V: Contains "S, T, Q, V". There is no SV block. Violates Rule 3. Invalid.
- (E) X, T, R, Q, S, V: - Starts with X (ok, Rule 1). - Ends with V (ok, Rule 2). - Contains an SV block (S is 5th, V is 6th) (ok, Rule 3). - R (3rd) is before S (5th) (ok, Rule 4). - All rules are satisfied. This corresponds to our Scenario 2 framework. Valid.
Step 4: Final Answer:
Only sequence (E) satisfies all the conditions of the game.

Answer 2

Step 1: Understanding the Concept:
We are given a new condition, a "QS" block, and asked for a possible occupant of the second position.
Step 2: Key Formula or Approach:
Apply the new condition and see how it interacts with the initial rules to determine the possible sequences.
Step 3: Detailed Explanation:
1. We have a new block: QS.
2. Consider the start rule (Rule 1). If the trip starts with Q, then the sequence would be Q(1), S(2). However, Rule 4 requires R to be visited before S. Since there is no space for R before position 2, the trip cannot start with Q.
3. Therefore, the trip must start with X. This means X=1.
4. From our key deduction, if X=1, then V=6 and S=5. The sequence skeleton is X, \_, \_, \_, S, V.
5. Now we apply the new condition "QS". Since S is at position 5, Q must be at position 4.
6. The sequence is now: X, \_, \_, Q, S, V.
7. The remaining sites, R and T, must fill positions 2 and 3 in either order.
8. The question asks what can be the second site visited. Based on our deduction, the second site can be R or T.
9. Looking at the options, (C) Tunin (T) is a possibility.
Step 4: Final Answer:
The condition forces the trip to start with X and Q to be in the 4th position, leaving R and T to fill the 2nd and 3rd positions. Therefore, Tunin can be the second site visited.

Answer 3

Step 1: Understanding the Concept:
We need to find the latest possible position for T and then determine which site must be in the third position in that specific scenario.
Step 2: Key Formula or Approach:
Test the latest slots for T (position 6, 5, etc.) and see if a valid schedule can be constructed. The first one that works gives us the scenario to analyze.
Step 3: Detailed Explanation:
1. Can T be 6th? No, the 6th position must be V or X (Rule 2).
2. Can T be 5th? Let's try to build a sequence: \_, \_, \_, \_, T, \_.
- The 6th site must be V or X. If it's V, then S must be in the 5th position, which is occupied by T. So the 6th site must be X. Sequence: \_, \_, \_, \_, T, X.
- The 1st site must be Q or X. Since X is last, the 1st site must be Q. Sequence: Q, \_, \_, \_, T, X.
- We need to place the R...SV chain in slots 2, 3, and 4. The only way to do this is R in 2, S in 3, and V in 4.
- This gives the complete sequence: Q, R, S, V, T, X.
- Let's check if this is valid: Starts Q (ok), ends X (ok), has SV block (ok), has R...S (ok). The sequence is valid.
3. So, the latest possible position for T is 5th, and the only sequence that allows this is Q, R, S, V, T, X.
4. The question asks which site must be the third in this scenario. Looking at the sequence, the third site is S (Sud).
Step 4: Final Answer:
The latest T can be visited is fifth, which forces a unique sequence where Sud is the third site visited.

Answer 4

Step 1: Understanding the Concept:
We are given a new spacing rule, T \_ X, and must find a necessary consequence.
Step 2: Key Formula or Approach:
Test the possible positions for the T \_ X block within the six slots and eliminate those that conflict with the main rules.
Step 3: Detailed Explanation:
1. The condition creates a `T \_ X` block. Let's test its placement.
- T=1, X=3: Impossible, start must be Q or X.
- T=4, X=6: Possible. Sequence: \_, \_, \_, T, \_, X. Start must be Q. Sequence: Q, \_, \_, T, \_, X. We need to place R,S,V in 2,3,5 with `R...SV`. `SV` must be a block. They can't fit. Impossible.
- T=3, X=5: Possible. Sequence: \_, \_, T, \_, X, \_. Start must be Q. End must be V. Sequence: Q, \_, T, \_, X, V. S must be before V, but there is no room for the `SV` block. Impossible.
- T=2, X=4: Possible. Sequence: \_, T, \_, X, \_, \_. Start must be Q. End must be V. Sequence: Q, T, \_, X, \_, V. The `SV` block means S=5. Sequence: Q, T, \_, X, S, V. The only remaining site is R, which must go in position 3.
2. The only possible sequence is: Q, T, R, X, S, V.
3. Let's verify this sequence: Starts Q (ok), ends V (ok), has `SV` block (ok, 5-6), has `R...S` (ok, 3...5), has `T \_ X` (ok, 2-4). It is a valid sequence.
4. Since this is the only possible sequence under the condition, we can determine what must be true.
5. Looking at the options:
- (A) Quin is visited second. False (it's first).
- (B) Ram is visited third. True.
- (C) Sud is visited fourth. False (X is fourth).
- (D) Vara is visited fifth. False (S is fifth).
- (E) Xilat is visited sixth. False (V is sixth).
Step 4: Final Answer:
The T \_ X spacing condition forces a unique sequence, in which Ram must be the third site visited.

Answer 5

Step 1: Understanding the Concept:
Given a new block, RX, we need to find a necessary consequence for the sequence.
Step 2: Key Formula or Approach:
Combine the new `RX` block with the existing `R...SV` chain. This gives a longer chain: `RX ... SV`. Then, determine where this long chain can fit in the sequence.
Step 3: Detailed Explanation:
1. The condition gives us an `RX` block.
2. Rule 1 states the trip must start with Q or X. It cannot start with X, because R must come immediately before it. Therefore, the trip must start with Q. So, Q=1.
3. Rule 2 states the trip must end with V or X. It cannot end with X, because there is no space for R before it at the end. Therefore, the trip must end with V. So, V=6.
4. Since V=6, the `SV` block means S must be at position 5.
5. The sequence skeleton is: Q, \_, \_, \_, S, V.
6. We need to place the `RX` block and the remaining site T into positions 2, 3, and 4. The `R...S` rule is already satisfied because R will be in 2, 3, or 4.
7. Two possible scenarios emerge: - Scenario A: The `RX` block is in 2-3. T is in 4. Sequence: Q, R, X, T, S, V. - Scenario B: The `RX` block is in 3-4. T is in 2. Sequence: Q, T, R, X, S, V. 8. We must find a statement that is true in both scenarios.
- (A) Q after T: False in Scenario A. Not a must.
- (B) R after Q: In both scenarios, Q is at position 1 and R is at position 2 or 3. So R is always visited after Q. This must be true.
- (C) T after R: False in Scenario B. Not a must.
- (D) T after S: False in both scenarios. Not a must.
- (E) X after S: False in both scenarios. Not a must.
Step 4: Final Answer:
The conditions force the trip to start with Quin, and in all possible resulting sequences, Ram is visited later.

Answer 6

Step 1: Understanding the Concept:
Given a fixed position for R, we must determine what other position is now fixed.
Step 2: Key Formula or Approach:
Place R at position 4 and see what consequences follow from the `R...SV` chain.
Step 3: Detailed Explanation:
1. We are given that R is at position 4. The sequence is \_, \_, \_, R, \_, \_.
2. We have the `R...SV` chain. Since R is at 4, S must be at 5 or 6, and V must be immediately after S.
3. The only way to fit the `SV` block after R=4 is to have S at position 5 and V at position 6.
4. The sequence is now fixed at the end: \_, \_, \_, R, S, V.
5. This immediately tells us that V (Vara) must be the sixth site visited. This matches option (D).
6. Let's quickly check if other options could be "musts". - The first three positions must be filled by Q, T, and X. - Rule 1 says position 1 must be Q or X. - So, it is not a must that Q is first (A). It is not a must that T is second or third (B, C). It is false that X is sixth (E).
Step 4: Final Answer:
Placing Ram in the fourth position forces Sud into the fifth and Vara into the sixth position to satisfy the ordering rules. Therefore, it must be true that Vara is the sixth site visited.

Answer 7

Step 1: Understanding the Concept:
This is a general "could be true" question, asking which statement is possible under the initial rules. We need to test each option to see if a valid schedule can be constructed.
Step 2: Key Formula or Approach:
For each option, assume the statement is true and try to build a complete, valid sequence. If you can build one, the statement "can be true." If it leads to a contradiction, it's false.
Step 3: Detailed Explanation:
- (A) Q is 5th? \_, \_, \_, \_, Q, \_. Start must be X. End must be V. X, \_, \_, \_, Q, V. S must be before V, but S must be at position 5, which is taken by Q. Contradiction. False.
- (B) R is 5th? \_, \_, \_, \_, R, \_. `R...S` means S must be 6th. `SV` block means V must be 7th. Impossible. False.
- (C) S is 2nd? \_, S, \_, \_, \_, \_. `SV` block means V=3. `R...S` means R=1. R, S, V, \_, \_, \_. But start must be Q or X. Contradiction. False.
- (D) X is 2nd? \_, X, \_, \_, \_, \_. Start must be Q. Q, X, \_, \_, \_, \_. End must be V. Q, X, \_, \_, \_, V. `SV` block means S=5. Q, X, \_, \_, S, V. We need to place R and T in 3 and 4. `R...S` rule requires R to be before S=5. This is possible (R could be 3 or 4). For example, a valid sequence is: Q, X, R, T, S, V. This "can be true". True.
- (E) X is 5th? \_, \_, \_, \_, X, \_. End must be V. \_, \_, \_, \_, X, V. `SV` block means S=5. But X is at 5. Contradiction. False.
Step 4: Final Answer:
It is possible to construct a valid schedule where Xilat is the second site visited (e.g., Q, X, R, T, S, V). All other options lead to contradictions.