A sample of radioactive element containing 4×1016 active nuclei. Half-life of the element is 10 days, then the number of decayed nuclei after 30 days
0.5 × 1016
2 × 1016
3.5 × 1016
1 × 1016
The correct option is (C) : 3.5 × 1016
t = nT, X = \(\frac{X_0}{2^m}n\) =\(\frac{t}{T}\)=\(\frac{30}{10}\)=3 , Active nuclei X = \(\frac{4\times10^{16}}{(2)^3}\) and decayed nuclie X = (X0 – X) = 3.5 × 1016
The current passing through the battery in the given circuit, is:
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In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.
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