A sample of radioactive element containing 4×1016 active nuclei. Half-life of the element is 10 days, then the number of decayed nuclei after 30 days
0.5 × 1016
2 × 1016
3.5 × 1016
1 × 1016
The correct option is (C) : 3.5 × 1016
t = nT, X = \(\frac{X_0}{2^m}n\) =\(\frac{t}{T}\)=\(\frac{30}{10}\)=3 , Active nuclei X = \(\frac{4\times10^{16}}{(2)^3}\) and decayed nuclie X = (X0 – X) = 3.5 × 1016
In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.
Read More: Nuclei