When magnesium carbonate ($MgCO_3$) is dissolved in dilute hydrochloric acid (HCl), it reacts to form magnesium chloride (MgCl₂) and carbonic acid (H₂CO₃):
$MgCO_3 + 2HCl \rightarrow MgCl_2 + H_2CO_3$ The carbonic acid then decomposes into water and carbon dioxide:
$H_2CO_3 \rightarrow H_2O + CO_2$ After this reaction, magnesium chloride (MgCl₂) remains in solution.
Next, the solution is neutralized with ammonia (NH₃) and buffered with NH₄Cl/NH₄OH. This creates a slightly alkaline medium.
When disodium hydrogen phosphate (Na₂HPO₄) is added to the solution, it reacts with magnesium ions (Mg²⁺) to form a precipitate. The reaction leads to the formation of magnesium ammonium phosphate (Mg(NH₄)PO₄), which is a white precipitate.
The formula of the precipitate is:
Answer: Mg(NH₄)PO₄
An aqueous solution of Co(ClO4)2·6H2O is light pink in colour. Addition of conc. HCl results in an intense blue coloured solution due to the formation of a new species. The new species among the following is:
[Given: Atomic number of Co = 27]
Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.
A beam of light of wavelength \(\lambda\) falls on a metal having work function \(\phi\) placed in a magnetic field \(B\). The most energetic electrons, perpendicular to the field, are bent in circular arcs of radius \(R\). If the experiment is performed for different values of \(\lambda\), then the \(B^2 \, \text{vs} \, \frac{1}{\lambda}\) graph will look like (keeping all other quantities constant).