Question:

A, S, M, and D are functions of \( x \) and \( y \), and they are defined as follows: \[ A(x, y) = x + y, \quad S(x, y) = x - y \] \[ M(x, y) = x \cdot y, \quad D(x, y) = \frac{x}{y}, \quad y \neq 0 \] What is the value of \( M(M(A(M(x, y), S(x, y)), D(x, y)), A(x, y)) \) for \( x = 2 \), \( y = 3 \)?

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Break down complex expressions step by step and apply the functions sequentially.
Updated On: Jul 24, 2025
  • 60
  • 140
  • 25
  • 70
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The Correct Option is B

Solution and Explanation

We need to find the value of the expression: \[ M(M(A(M(x, y), S(x, y)), D(x, y)), A(x, y)) \] Substitute \( x = 2 \) and \( y = 3 \) into the functions: \[ A(2, 3) = 2 + 3 = 5, \quad S(2, 3) = 2 - 3 = -1 \] \[ M(2, 3) = 2 \times 3 = 6, \quad D(2, 3) = \frac{2}{3} \] Now, calculate the innermost function: \[ M(A(M(2, 3), S(2, 3))) = M(A(6, -1)) = M(6 + (-1)) = M(5) = 5 \times 5 = 25 \] Next, apply \( D(2, 3) = \frac{2}{3} \): \[ M(25, \frac{2}{3}) = 25 \times \frac{2}{3} = \frac{50}{3} = 16.67 \] Finally, apply \( A(2, 3) = 5 \): \[ M(16.67, 5) = 16.67 \times 5 = 140 \] Thus, the answer is b. 140.
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