A right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm. Find the volume of the solid so obtained.
Solution and Explanation
When right-angled \(∆ABC\) is revolved about its side 12 cm, a cone with height (h) as 12 cm, radius (r) as 5 cm, and slant height (\(l\)) 13 cm will be formed.
Volume of cone= \(\frac{1}{3}\pi\)r²h
= \(\frac{1}{3}\) × \(\pi\) × 5 cm × 5 cm × 12 cm
= 100\(\pi\) cm³
Volume of the cone is 100\(\pi\) cm³
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