Question:

A resistor of resistance \( R \), inductor of inductive reactance \( 2R \) and a capacitor of capacitive reactance \( X_C \) are connected in series to an A.C. source. If the series LCR circuit is in resonance, then the power factor of the circuit and the value \( X_C \) are respectively:

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At resonance, \( X_L = X_C \) and the power factor is always \( 1 \).
Updated On: Mar 24, 2025
  • \( 0.5 \) and \( 4R \)
  • \( 1 \) and \( 2R \)
  • \( 0.5 \) and \( 2R \)
  • \( 1 \) and \( 4R \)
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The Correct Option is B

Solution and Explanation

Step 1: Resonance Condition At resonance, inductive reactance equals capacitive reactance: \[ X_L = X_C \] Step 2: Compute \( X_C \) \[ X_C = 2R \] Step 3: Compute Power Factor At resonance, power factor is given by: \[ \cos \phi = 1 \] Thus, the correct answer is \( 1 \) and \( 2R \).
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