Question

A residential housing project is designed in a plot measuring 1 hectare. The car parking area is equally distributed between the ground floor and the basement. Considering the data given below, the number of cars accommodated in the basement will be \underline{\hspace{2cm}} [in integer]. Data: - FAR consumed = 2.0
- Car parking area is exempted from built up area for FAR calculations.
- One car parking to be given for each 100 sq.m of built up area.
- Area required for accommodating each car in ground floor = 15 sq.m
- Area required for accommodating each car in basement = 25 sq.m

Hint:

Be careful: In such parking problems, the area distribution is key, not directly the number of cars. Always compute total parking area, split equally, then divide by area requirement per car.

Answer 1

Step 1: Calculate plot area.
\[ \text{Plot area} = 1 \; \text{hectare} = 10{,}000 \; \text{m}^2 \]

Step 2: Built-up area using FAR.
\[ \text{Built-up area} = FAR \times \text{Plot area} = 2.0 \times 10{,}000 = 20{,}000 \; \text{m}^2 \]

Step 3: Car parking requirement.
One car parking required for every 100 sq.m built-up area.
\[ \text{Required parking spaces} = \frac{20{,}000}{100} = 200 \; \text{cars} \]

Step 4: Distribution of parking between ground floor and basement.
Parking area is distributed equally: \[ 200 \div 2 = 100 \; \text{cars in ground floor (minimum allocation)}, 100 \; \text{cars in basement} \]

Step 5: Area requirement and adjustment.
- Ground floor: Each car requires 15 sq.m
\[ 100 \times 15 = 1500 \; \text{m}^2 \] - Basement: Each car requires 25 sq.m. Initially, 100 cars → \[ 100 \times 25 = 2500 \; \text{m}^2 \] But — the parking area allocation is by total requirement, not fixed per car count.

Step 6: Total area required for 200 cars.
Since ground and basement must share equally in terms of area, not car count, we calculate: Total area needed if all were in ground = \(200 \times 15 = 3000\) m\(^2\).
Total area needed if all were in basement = \(200 \times 25 = 5000\) m\(^2\). But given: Area is equally split. \[ \text{Total parking area required} = 200 \times \text{average area per car} \] Weighted average area = \(\frac{15+25}{2} = 20\) m\(^2\)/car
\[ \text{Total parking area} = 200 \times 20 = 4000 \; \text{m}^2 \] So each level (ground + basement) gets: \[ \frac{4000}{2} = 2000 \; \text{m}^2 \]

Step 7: Cars accommodated in basement.
\[ \text{No. of cars in basement} = \frac{2000}{25} = 80 \; \text{cars} \] Wait — check again carefully: The question states parking area equally distributed between ground and basement, not number of cars.

Step 8: Correct calculation.
- Total parking spaces required = 200.
- Each car requires 100 sq.m built-up ÷ FAR ÷ ratio → correction not needed. - Equal area distribution: 2000 m\(^2\) basement / 25 m\(^2\) per car = 80 cars.

Final Answer: \[ \boxed{80 \; \text{cars}} \]