Step 1: Check reflexivity. For reflexivity, \( (x, x) \) must belong to \( R \), but \( x \) cannot be 5 cm shorter than itself. Thus, \( R \) is not reflexive.
Step 2: Check symmetry. For symmetry, if \( (x, y) \in R \), then \( (y, x) \in R \). Since \( x \) is 5 cm shorter than \( y \), the reverse is not true, so \( R \) is not symmetric.
Step 3: Check transitivity. For transitivity, if \( (x, y) \in R \) and \( (y, z) \in R \), then \( (x, z) \in R \). However, \( x \) is 5 cm shorter than \( y \) and \( y \) is 5 cm shorter than \( z \), making \( x \) 10 cm shorter than \( z \). Thus, \( R \) is not transitive.
Final Answer: \[ \boxed{\text{Neither transitive, nor symmetric, nor reflexive}} \]
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
State and elaborate, whether the following statements are true/false, with valid arguments
Under the Golden Revolution there was tremendous growth in horticulture, making India the world leader in this field.