Step 1: Check reflexivity. For reflexivity, \( (x, x) \) must belong to \( R \), but \( x \) cannot be 5 cm shorter than itself. Thus, \( R \) is not reflexive.
Step 2: Check symmetry. For symmetry, if \( (x, y) \in R \), then \( (y, x) \in R \). Since \( x \) is 5 cm shorter than \( y \), the reverse is not true, so \( R \) is not symmetric.
Step 3: Check transitivity. For transitivity, if \( (x, y) \in R \) and \( (y, z) \in R \), then \( (x, z) \in R \). However, \( x \) is 5 cm shorter than \( y \) and \( y \) is 5 cm shorter than \( z \), making \( x \) 10 cm shorter than \( z \). Thus, \( R \) is not transitive.
Final Answer: \[ \boxed{\text{Neither transitive, nor symmetric, nor reflexive}} \]
Let $R$ be a relation defined on the set $\{1,2,3,4\times\{1,2,3,4\}$ by \[ R=\{((a,b),(c,d)) : 2a+3b=3c+4d\} \] Then the number of elements in $R$ is
Let \(M = \{1, 2, 3, ....., 16\}\), if a relation R defined on set M such that R = \((x, y) : 4y = 5x – 3, x, y (\in) M\). How many elements should be added to R to make it symmetric.