To determine the original price per kg of sugar, we start by considering the information given:
A person spends Rs. 240 and with a 20% reduction in price, they can buy 6 kg more sugar.
- Let the original price per kg be Rs. x.
- The reduced price after a 20% decrease is \(0.8 \times x = 0.8x\).
- Let the original quantity bought with Rs. 240 be \(q\) kg. So, \(q = \frac{240}{x}\).
- At the reduced price, the person can buy 6 kg more, meaning \(\frac{240}{0.8x} = q + 6\).
- Substituting the value of \(q\):
\(\frac{240}{0.8x} = \frac{240}{x} + 6\)
- Simplify the equation: \(\frac{240}{0.8x} - \frac{240}{x} = 6\).
- Find a common denominator:
\(\frac{240x - 240 \times 0.8x}{0.8x \times x} = 6\)
- Simplify: \(\frac{240x - 192x}{0.8x^2} = 6\)
- This becomes \(\frac{48x}{0.8x^2} = 6\).
- Cancel \(x\) from numerator and denominator:
\(\frac{48}{0.8x} = 6\)
- Rearrange: \(48 = 4.8x\).
- Solve for \(x\): \(x = \frac{48}{4.8} = 10\).
The original price per kg of sugar is Rs. 10.