The formula can be expressed as i = Ɛ/R
Now, Ɛ = NA (dB/dt)
According to the problem– N=20, A=25cm2= 25x10-4 cm2, R=100Ω, dB/dt= 1000Ts-1
Therefore, i =[NA(dB/dt)] / R = [20x25x10-4x1000] / 100
∴ i = 2x25x0.01 = 0.5A
So, the resultant current is 0.5 amp.
A wire coil wound around an electrical conductor is referred to as a current coil. The wire in this case is typically insulated copper wire. A soft iron core serves as the conductor. Electromagnetism is shown via the current coil conductor experiment.
A few applications of such coil are–
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where