A rectangle's length is twice its breadth. If the perimeter is 60 cm, what is its area?
250 cm²
- Step 1: Represent dimensions - Let breadth = $b$ cm, length = $2b$ cm.
- Step 2: Perimeter formula - \[ P = 2(\text{length} + \text{breadth}) = 2(2b + b) = 6b \] Given $P = 60$, so: \[ 6b = 60 \implies b = 10 \ \text{cm} \]
- Step 3: Finding length - $l = 2b = 20$ cm.
- Step 4: Area formula - \[ \text{Area} = l \times b = 20 \times 10 = 200 \ \text{cm}^2 \]
- Step 5: Conclusion - Area is $200\ \text{cm}^2$, matching option (3).
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: