Step 1: Understanding the effects of increasing the width of a rectangle by 10%.
The dimensions of the rectangle are \(L\) (length) and \(W\) (width), with \(L>W\). When the width \(W\) is increased by 10%, the new width becomes \(W' = 1.1W\), while the length \(L\) remains the same.
Step 2: Analyzing the impact on each option.
Option (A) Perimeter increases by 10%:
The perimeter of a rectangle is given by the formula:
\[
P = 2(L + W)
\]
When the width increases by 10%, the new perimeter becomes:
\[
P' = 2(L + 1.1W)
\]
This is not exactly a 10% increase. The increase in perimeter is not proportional to the increase in width. Therefore, this option is incorrect.
Option (B) Length of the diagonals increases by 10%:
The diagonal \(d\) of a rectangle is given by the Pythagorean theorem:
\[
d = \sqrt{L^2 + W^2}
\]
When the width increases by 10%, the new diagonal is:
\[
d' = \sqrt{L^2 + (1.1W)^2}
\]
This increase is not guaranteed to be exactly 10%. The length of the diagonal increases, but it is not necessarily a 10% increase. Therefore, this option is incorrect.
Option (C) Area increases by 10%:
The area \(A\) of a rectangle is given by:
\[
A = L \times W
\]
After increasing the width by 10%, the new area is:
\[
A' = L \times 1.1W = 1.1 \times L \times W
\]
This shows that the area increases by 10%, as the new area is 1.1 times the original area. Therefore, this option is correct.
Option (D) The rectangle becomes a square:
A rectangle becomes a square only if the length and width are equal. Since only the width is increased by 10%, the rectangle does not become a square. Therefore, this option is incorrect.
Therefore, the correct answer is Option (C) Area increases by 10%.