Question

A random survey of the number of children of various age groups playing in a park was found as follows:

Age (in years)	Number of children
1 − 2	5
2 − 3	3
3 − 5	6
5 − 7	12
7 − 10	9
10 − 15	10
15 − 17	4

Draw a histogram to represent the data above.

Answer 1

Here, it can be observed that the data has class intervals of varying width. The proportion of children per 1 year interval can be calculated as follows.   

Age (In years)	Frequency (Number of children)	Width of classes	Length of rectangle
1 − 2	5	1	\(\frac{5 \times 1}{1}=5\)
2 − 3	3	1	\(\frac{3 \times 1}{1}=3\)
3 − 5	6	2	\(\frac{6 \times 1}{1}=6\)
5 − 7	12	2	\(\frac{12 \times 1}{1}=12\)
7 − 10	9	3	\(\frac{9 \times 1}{1}=9\)
10 − 15	10	5	\(\frac{10 \times 1}{1}=10\)
15 − 17	4	2	\(\frac{4 \times 1}{1}=4\)

 
Taking the age of children on x-axis and proportion of children per 1 year interval on yaxis, the histogram can be drawn as follows.