A radio transmitter operates at a frequency 880 kHz and a power of 10 kW. The number of photons emitted per second is
- $1.72 \times 10^{31}$
- $1.327 \times 10^{25}$
- $1.327 \times 10^{37}$
- $1.327 \times 10^{45}$
The Correct Option is A
Solution and Explanation
$ n = \frac {Power}{Energy\, of\, photon}$
$ = \frac{P}{h\upsilon} = \frac{10000}{6.6 \times 10^{-34} \times 880 \times 10^{3}}$
$ = 1.72 \times 10^{31} $
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Concepts Used:
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The dual nature of matter and the dual nature of radiation were throughgoing concepts of physics. At the beginning of the 20th century, scientists untangled one of the best-kept secrets of nature – the wave-particle duplexity or the dual nature of matter and radiation.
Electronic Emission
The least energy that is needed to emit an electron from the surface of a metal can be supplied to the loose electrons.
Photoelectric Effect
The photoelectric effect is a phenomenon that involves electrons getting away from the surface of materials.
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Heisenberg’s Uncertainty Principle states that both the momentum and position of a particle cannot be determined simultaneously.