The fraction of a radioactive element that decays over a given period of time is given by the formula: \[ N(t) = N_0 \left(\frac{1}{2}\right)^{\frac{t}{T_{1/2}}} \] Where:
\(N(t)\) is the amount of the substance remaining after time \(t\),
\(N_0\) is the initial amount of the substance,
\(T_{1/2}\) is the half-life of the substance.
The fraction that decays is given by: \[ \text{Fraction decayed} = 1 - \left(\frac{1}{2}\right)^{\frac{t}{T_{1/2}}} \]
Given:
\(T_{1/2} = 15 \, \text{years}\),
\(t = 30 \, \text{years}\). Substitute the values: \[ \text{Fraction decayed} = 1 - \left(\frac{1}{2}\right)^{\frac{30}{15}} = 1 - \left(\frac{1}{2}\right)^2 = 1 - \frac{1}{4} = 0.75 \] Thus, the fraction that will decay in 30 years is 0.75.
The correct answer is (C) : 0.75.